37n^2+16n=0

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Solution for 37n^2+16n=0 equation:



37n^2+16n=0
a = 37; b = 16; c = 0;
Δ = b2-4ac
Δ = 162-4·37·0
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-16}{2*37}=\frac{-32}{74} =-16/37 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+16}{2*37}=\frac{0}{74} =0 $

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